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10312243001 is a prime number
BaseRepresentation
bin10011001101010100…
…00101011100111001
3222121200022012222222
421212222011130321
5132104413234001
64423135053425
7513355422254
oct114652053471
928550265888
1010312243001
114411aa0885
121bb9671275
13c845b3a48
146db80209b
154054d961b
hex266a85739

10312243001 has 2 divisors, whose sum is σ = 10312243002. Its totient is φ = 10312243000.

The previous prime is 10312242977. The next prime is 10312243003. The reversal of 10312243001 is 10034221301.

10312243001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8994625600 + 1317617401 = 94840^2 + 36299^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10312243001 is a prime.

Together with 10312243003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10312243003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156121500 + 5156121501.

It is an arithmetic number, because the mean of its divisors is an integer number (5156121501).

Almost surely, 210312243001 is an apocalyptic number.

It is an amenable number.

10312243001 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312243001 is an equidigital number, since it uses as much as digits as its factorization.

10312243001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10312243001 its reverse (10034221301), we get a palindrome (20346464302).

The spelling of 10312243001 in words is "ten billion, three hundred twelve million, two hundred forty-three thousand, one".