Base | Representation |
---|---|
bin | 10011001101010100… |
… | …00101101100110001 |
3 | 222121200022021101121 |
4 | 21212222011230301 |
5 | 132104413302032 |
6 | 4423135102241 |
7 | 513355425235 |
oct | 114652055461 |
9 | 28550267347 |
10 | 10312244017 |
11 | 4411aa1619 |
12 | 1bb9671981 |
13 | c845b434a |
14 | 6db8025c5 |
15 | 4054d9a97 |
hex | 266a85b31 |
10312244017 has 2 divisors, whose sum is σ = 10312244018. Its totient is φ = 10312244016.
The previous prime is 10312244003. The next prime is 10312244069. The reversal of 10312244017 is 71044221301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5781473296 + 4530770721 = 76036^2 + 67311^2 .
It is a cyclic number.
It is not a de Polignac number, because 10312244017 - 215 = 10312211249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10312243982 and 10312244000.
It is not a weakly prime, because it can be changed into another prime (10312244077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156122008 + 5156122009.
It is an arithmetic number, because the mean of its divisors is an integer number (5156122009).
Almost surely, 210312244017 is an apocalyptic number.
It is an amenable number.
10312244017 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312244017 is an equidigital number, since it uses as much as digits as its factorization.
10312244017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 10312244017 its reverse (71044221301), we get a palindrome (81356465318).
The spelling of 10312244017 in words is "ten billion, three hundred twelve million, two hundred forty-four thousand, seventeen".
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