Base | Representation |
---|---|
bin | 110000000001010011… |
… | …1000001111101111101 |
3 | 100212011211010020112022 |
4 | 1200002213001331331 |
5 | 3142143442014323 |
6 | 115212443445525 |
7 | 10310325022211 |
oct | 1400247017575 |
9 | 325154106468 |
10 | 103123001213 |
11 | 3a809278141 |
12 | 17b9b8268a5 |
13 | 995582bc5b |
14 | 4dc3b24941 |
15 | 2a384c84c8 |
hex | 18029c1f7d |
103123001213 has 2 divisors, whose sum is σ = 103123001214. Its totient is φ = 103123001212.
The previous prime is 103123001173. The next prime is 103123001251. The reversal of 103123001213 is 312100321301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54104155609 + 49018845604 = 232603^2 + 221402^2 .
It is a cyclic number.
It is not a de Polignac number, because 103123001213 - 222 = 103118806909 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 103123001191 and 103123001200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103123003213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51561500606 + 51561500607.
It is an arithmetic number, because the mean of its divisors is an integer number (51561500607).
Almost surely, 2103123001213 is an apocalyptic number.
It is an amenable number.
103123001213 is a deficient number, since it is larger than the sum of its proper divisors (1).
103123001213 is an equidigital number, since it uses as much as digits as its factorization.
103123001213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 103123001213 its reverse (312100321301), we get a palindrome (415223322514).
The spelling of 103123001213 in words is "one hundred three billion, one hundred twenty-three million, one thousand, two hundred thirteen".
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