Base | Representation |
---|---|
bin | 10111011100101001001001… |
… | …110011111000011010011111 |
3 | 111112010111112021022112012211 |
4 | 113130221021303320122133 |
5 | 102004033212144123033 |
6 | 1003154123135141251 |
7 | 30502264030436326 |
oct | 2734511163703237 |
9 | 445114467275184 |
10 | 103123403114143 |
11 | 2a9494316aaaa5 |
12 | b69600b074827 |
13 | 4570658c065c9 |
14 | 1b672b0dcd0bd |
15 | bdc722b392cd |
hex | 5dca49cf869f |
103123403114143 has 2 divisors, whose sum is σ = 103123403114144. Its totient is φ = 103123403114142.
The previous prime is 103123403114129. The next prime is 103123403114167. The reversal of 103123403114143 is 341411304321301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103123403114143 - 237 = 102985964160671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103123403111143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51561701557071 + 51561701557072.
It is an arithmetic number, because the mean of its divisors is an integer number (51561701557072).
Almost surely, 2103123403114143 is an apocalyptic number.
103123403114143 is a deficient number, since it is larger than the sum of its proper divisors (1).
103123403114143 is an equidigital number, since it uses as much as digits as its factorization.
103123403114143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 103123403114143 its reverse (341411304321301), we get a palindrome (444534707435444).
The spelling of 103123403114143 in words is "one hundred three trillion, one hundred twenty-three billion, four hundred three million, one hundred fourteen thousand, one hundred forty-three".
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