10312433113 has 2 divisors, whose sum is σ = 10312433114. Its totient is φ = 10312433112.

The previous prime is 10312433107. The next prime is 10312433149. The reversal of 10312433113 is 31133421301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8392941769 + 1919491344 = 91613^2 + 43812^2 .

It is an emirp because it is prime and its reverse (31133421301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10312433113 - 2⁵ = 10312433081 is a prime.

It is not a weakly prime, because it can be changed into another prime (10312430113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156216556 + 5156216557.

It is an arithmetic number, because the mean of its divisors is an integer number (5156216557).

Almost surely, 2^10312433113 is an apocalyptic number.

It is an amenable number.

10312433113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312433113 is an equidigital number, since it uses as much as digits as its factorization.

10312433113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 10312433113 its reverse (31133421301), we get a palindrome (41445854414).

The spelling of 10312433113 in words is "ten billion, three hundred twelve million, four hundred thirty-three thousand, one hundred thirteen".