Base | Representation |
---|---|
bin | 10011001101010101… |
… | …10011110111111101 |
3 | 222121200122212211111 |
4 | 21212222303313331 |
5 | 132104440330044 |
6 | 4423143122021 |
7 | 513360143524 |
oct | 114652636775 |
9 | 28550585744 |
10 | 10312433149 |
11 | 4412110727 |
12 | 1bb9743311 |
13 | c8464c465 |
14 | 6db8514bb |
15 | 405525b34 |
hex | 266ab3dfd |
10312433149 has 2 divisors, whose sum is σ = 10312433150. Its totient is φ = 10312433148.
The previous prime is 10312433113. The next prime is 10312433237. The reversal of 10312433149 is 94133421301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5726705625 + 4585727524 = 75675^2 + 67718^2 .
It is a cyclic number.
It is not a de Polignac number, because 10312433149 - 213 = 10312424957 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10312433149.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312436149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156216574 + 5156216575.
It is an arithmetic number, because the mean of its divisors is an integer number (5156216575).
Almost surely, 210312433149 is an apocalyptic number.
It is an amenable number.
10312433149 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312433149 is an equidigital number, since it uses as much as digits as its factorization.
10312433149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 10312433149 in words is "ten billion, three hundred twelve million, four hundred thirty-three thousand, one hundred forty-nine".
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