Base | Representation |
---|---|
bin | 10011001101010101… |
… | …10011110111100001 |
3 | 222121200122212210110 |
4 | 21212222303313201 |
5 | 132104440324441 |
6 | 4423143121533 |
7 | 513360143454 |
oct | 114652636741 |
9 | 28550585713 |
10 | 10312433121 |
11 | 4412110701 |
12 | 1bb97432a9 |
13 | c8464c443 |
14 | 6db85149b |
15 | 405525b16 |
hex | 266ab3de1 |
10312433121 has 8 divisors (see below), whose sum is σ = 14558729184. Its totient is φ = 6470546240.
The previous prime is 10312433113. The next prime is 10312433149. The reversal of 10312433121 is 12133421301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10312433121 - 23 = 10312433113 is a prime.
It is a super-3 number, since 3×103124331213 (a number of 31 digits) contains 333 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (10312433821) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101102235 + ... + 101102336.
It is an arithmetic number, because the mean of its divisors is an integer number (1819841148).
Almost surely, 210312433121 is an apocalyptic number.
It is an amenable number.
10312433121 is a deficient number, since it is larger than the sum of its proper divisors (4246296063).
10312433121 is a wasteful number, since it uses less digits than its factorization.
10312433121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 202204591.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 10312433121 its reverse (12133421301), we get a palindrome (22445854422).
The spelling of 10312433121 in words is "ten billion, three hundred twelve million, four hundred thirty-three thousand, one hundred twenty-one".
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