10312433120 has 144 divisors (see below), whose sum is σ = 26942842080. Its totient is φ = 3727088640.

The previous prime is 10312433113. The next prime is 10312433149. The reversal of 10312433120 is 2133421301.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 10312433092 and 10312433101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3347741 + ... + 3350819.

It is an arithmetic number, because the mean of its divisors is an integer number (187103070).

Almost surely, 2^10312433120 is an apocalyptic number.

10312433120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10312433120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13471421040).

10312433120 is an abundant number, since it is smaller than the sum of its proper divisors (16630408960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10312433120 is a wasteful number, since it uses less digits than its factorization.

10312433120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3289 (or 3270 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 10312433120 its reverse (2133421301), we get a palindrome (12445854421).

The spelling of 10312433120 in words is "ten billion, three hundred twelve million, four hundred thirty-three thousand, one hundred twenty".