Base | Representation |
---|---|
bin | 1001011000010000110101… |
… | …1001010010100111001101 |
3 | 1100111212012202111022002201 |
4 | 2112010031121102213031 |
5 | 2322424334422230331 |
6 | 33533245312321501 |
7 | 2113022623000063 |
oct | 226041531224715 |
9 | 40455182438081 |
10 | 10312441211341 |
11 | 3316533245565 |
12 | 11a6753843291 |
13 | 59a5c765c239 |
14 | 2791a6700033 |
15 | 12d3b4976a61 |
hex | 9610d6529cd |
10312441211341 has 2 divisors, whose sum is σ = 10312441211342. Its totient is φ = 10312441211340.
The previous prime is 10312441211311. The next prime is 10312441211353. The reversal of 10312441211341 is 14311214421301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7671071908900 + 2641369302441 = 2769670^2 + 1625229^2 .
It is a cyclic number.
It is not a de Polignac number, because 10312441211341 - 27 = 10312441211213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312441211311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156220605670 + 5156220605671.
It is an arithmetic number, because the mean of its divisors is an integer number (5156220605671).
Almost surely, 210312441211341 is an apocalyptic number.
It is an amenable number.
10312441211341 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312441211341 is an equidigital number, since it uses as much as digits as its factorization.
10312441211341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 10312441211341 its reverse (14311214421301), we get a palindrome (24623655632642).
The spelling of 10312441211341 in words is "ten trillion, three hundred twelve billion, four hundred forty-one million, two hundred eleven thousand, three hundred forty-one".
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