10313000323 has 2 divisors, whose sum is σ = 10313000324. Its totient is φ = 10313000322.

The previous prime is 10313000311. The next prime is 10313000339. The reversal of 10313000323 is 32300031301.

It is an a-pointer prime, because the next prime (10313000339) can be obtained adding 10313000323 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10313000323 - 2⁹ = 10312999811 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10313000297 and 10313000306.

It is not a weakly prime, because it can be changed into another prime (10313000303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156500161 + 5156500162.

It is an arithmetic number, because the mean of its divisors is an integer number (5156500162).

Almost surely, 2^10313000323 is an apocalyptic number.

10313000323 is a deficient number, since it is larger than the sum of its proper divisors (1).

10313000323 is an equidigital number, since it uses as much as digits as its factorization.

10313000323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 16.

Adding to 10313000323 its reverse (32300031301), we get a palindrome (42613031624).

The spelling of 10313000323 in words is "ten billion, three hundred thirteen million, three hundred twenty-three", and thus it is an aban number.