Search a number
-
+
10313004500191 is a prime number
BaseRepresentation
bin1001011000010010111011…
…1110000100010011011111
31100111220200000102100010201
42112010232332010103133
52322432013123001231
633533421233444331
72113042602606451
oct226045676042337
940456600370121
1010313004500191
1133167a21a9838
1211a68904106a7
1359a687273253
1427921b44c2d1
1512d3e9142161
hex9612ef844df

10313004500191 has 2 divisors, whose sum is σ = 10313004500192. Its totient is φ = 10313004500190.

The previous prime is 10313004500173. The next prime is 10313004500261. The reversal of 10313004500191 is 19100540031301.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10313004500191 - 25 = 10313004500159 is a prime.

It is a super-4 number, since 4×103130045001914 (a number of 53 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10313004500101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156502250095 + 5156502250096.

It is an arithmetic number, because the mean of its divisors is an integer number (5156502250096).

Almost surely, 210313004500191 is an apocalyptic number.

10313004500191 is a deficient number, since it is larger than the sum of its proper divisors (1).

10313004500191 is an equidigital number, since it uses as much as digits as its factorization.

10313004500191 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 28.

Adding to 10313004500191 its reverse (19100540031301), we get a palindrome (29413544531492).

The spelling of 10313004500191 in words is "ten trillion, three hundred thirteen billion, four million, five hundred thousand, one hundred ninety-one".