103130311019 has 2 divisors, whose sum is σ = 103130311020. Its totient is φ = 103130311018.

The previous prime is 103130311013. The next prime is 103130311021. The reversal of 103130311019 is 910113031301.

It is a strong prime.

It is an emirp because it is prime and its reverse (910113031301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-103130311019 is a prime.

It is a super-2 number, since 2×103130311019² (a number of 23 digits) contains 22 as substring.

Together with 103130311021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 103130310985 and 103130311003.

It is not a weakly prime, because it can be changed into another prime (103130311013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565155509 + 51565155510.

It is an arithmetic number, because the mean of its divisors is an integer number (51565155510).

Almost surely, 2^103130311019 is an apocalyptic number.

103130311019 is a deficient number, since it is larger than the sum of its proper divisors (1).

103130311019 is an equidigital number, since it uses as much as digits as its factorization.

103130311019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 103130311019 in words is "one hundred three billion, one hundred thirty million, three hundred eleven thousand, nineteen".