Base | Representation |
---|---|
bin | 11110000000111101111… |
… | …11100100001110100111 |
3 | 10122120222220201111011222 |
4 | 33000132333210032213 |
5 | 113344111401142413 |
6 | 2105440034050555 |
7 | 134336606321441 |
oct | 17003677441647 |
9 | 3576886644158 |
10 | 1031312130983 |
11 | 3684168a23a2 |
12 | 147a60419a5b |
13 | 763384553b4 |
14 | 37cb6c4d491 |
15 | 1bc60679b08 |
hex | f01efe43a7 |
1031312130983 has 2 divisors, whose sum is σ = 1031312130984. Its totient is φ = 1031312130982.
The previous prime is 1031312130971. The next prime is 1031312131013. The reversal of 1031312130983 is 3890312131301.
It is a weak prime.
It is an emirp because it is prime and its reverse (3890312131301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1031312130983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031312130083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515656065491 + 515656065492.
It is an arithmetic number, because the mean of its divisors is an integer number (515656065492).
Almost surely, 21031312130983 is an apocalyptic number.
1031312130983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031312130983 is an equidigital number, since it uses as much as digits as its factorization.
1031312130983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 35.
The spelling of 1031312130983 in words is "one trillion, thirty-one billion, three hundred twelve million, one hundred thirty thousand, nine hundred eighty-three".
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