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1031314022134 = 211393111925187
BaseRepresentation
bin11110000000111110001…
…10110001111011110110
310122121000001021120100121
433000133012301323312
5113344112342202014
62105440142402154
7134336631356134
oct17003706617366
93577001246317
101031314022134
11368417974230
12147a60b9035a
1376338968116
1437cb71c2754
151bc60900124
hexf01f1b1ef6

1031314022134 has 16 divisors (see below), whose sum is σ = 1688034211776. Its totient is φ = 468659809800.

The previous prime is 1031314022119. The next prime is 1031314022183. The reversal of 1031314022134 is 4312204131301.

It is a super-2 number, since 2×10313140221342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1031314022099 and 1031314022108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5876112 + ... + 6049075.

It is an arithmetic number, because the mean of its divisors is an integer number (105502138236).

Almost surely, 21031314022134 is an apocalyptic number.

1031314022134 is a deficient number, since it is larger than the sum of its proper divisors (656720189642).

1031314022134 is a wasteful number, since it uses less digits than its factorization.

1031314022134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11929131.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1031314022134 its reverse (4312204131301), we get a palindrome (5343518153435).

The spelling of 1031314022134 in words is "one trillion, thirty-one billion, three hundred fourteen million, twenty-two thousand, one hundred thirty-four".

Divisors: 1 2 11 22 3931 7862 43241 86482 11925187 23850374 131177057 262354114 46877910097 93755820194 515657011067 1031314022134