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10313211040453 is a prime number
BaseRepresentation
bin1001011000010011101101…
…0001111101001011000101
31100111221012102001200010001
42112010323101331023011
52322432424011243303
633533453532401301
72113050661303606
oct226047321751305
940457172050101
1010313211040453
113316898849572
1211a6929616231
1359a6bacaa419
1427923aa53dad
1512d40c33e31d
hex9613b47d2c5

10313211040453 has 2 divisors, whose sum is σ = 10313211040454. Its totient is φ = 10313211040452.

The previous prime is 10313211040381. The next prime is 10313211040471. The reversal of 10313211040453 is 35404011231301.

10313211040453 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5444648224129 + 4868562816324 = 2333377^2 + 2206482^2 .

It is a cyclic number.

It is not a de Polignac number, because 10313211040453 - 225 = 10313177486021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10313211040553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156605520226 + 5156605520227.

It is an arithmetic number, because the mean of its divisors is an integer number (5156605520227).

Almost surely, 210313211040453 is an apocalyptic number.

It is an amenable number.

10313211040453 is a deficient number, since it is larger than the sum of its proper divisors (1).

10313211040453 is an equidigital number, since it uses as much as digits as its factorization.

10313211040453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 10313211040453 its reverse (35404011231301), we get a palindrome (45717222271754).

The spelling of 10313211040453 in words is "ten trillion, three hundred thirteen billion, two hundred eleven million, forty thousand, four hundred fifty-three".