Base | Representation |
---|---|
bin | 110000000001100110… |
… | …1100110101011010100 |
3 | 100212012112010222100120 |
4 | 1200003031212223110 |
5 | 3142204034104134 |
6 | 115213444311540 |
7 | 10310506665603 |
oct | 1400315465324 |
9 | 325175128316 |
10 | 103133113044 |
11 | 3a813a54325 |
12 | 17ba30a25b0 |
13 | 995795c6a0 |
14 | 4dc51d7a3a |
15 | 2a39324649 |
hex | 1803366ad4 |
103133113044 has 24 divisors (see below), whose sum is σ = 259155002400. Its totient is φ = 31733265504.
The previous prime is 103133113043. The next prime is 103133113049. The reversal of 103133113044 is 440311331301.
103133113044 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1031331130442 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103133113043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 330554694 + ... + 330555005.
It is an arithmetic number, because the mean of its divisors is an integer number (10798125100).
Almost surely, 2103133113044 is an apocalyptic number.
It is an amenable number.
103133113044 is an abundant number, since it is smaller than the sum of its proper divisors (156021889356).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103133113044 is a wasteful number, since it uses less digits than its factorization.
103133113044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 661109719 (or 661109717 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 103133113044 its reverse (440311331301), we get a palindrome (543444444345).
The spelling of 103133113044 in words is "one hundred three billion, one hundred thirty-three million, one hundred thirteen thousand, forty-four".
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