Base | Representation |
---|---|
bin | 10011001101011110… |
… | …00101011000010111 |
3 | 222121202202210120102 |
4 | 21212233011120113 |
5 | 132110232202211 |
6 | 4423223124315 |
7 | 513402520616 |
oct | 114657053027 |
9 | 28552683512 |
10 | 10313553431 |
11 | 4412806385 |
12 | 1bb9ba369b |
13 | c8495234c |
14 | 6dba6387d |
15 | 405697a3b |
hex | 266bc5617 |
10313553431 has 2 divisors, whose sum is σ = 10313553432. Its totient is φ = 10313553430.
The previous prime is 10313553427. The next prime is 10313553451. The reversal of 10313553431 is 13435531301.
It is a weak prime.
It is an emirp because it is prime and its reverse (13435531301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10313553431 - 22 = 10313553427 is a prime.
It is a super-2 number, since 2×103135534312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10313553394 and 10313553403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10313553451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156776715 + 5156776716.
It is an arithmetic number, because the mean of its divisors is an integer number (5156776716).
Almost surely, 210313553431 is an apocalyptic number.
10313553431 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313553431 is an equidigital number, since it uses as much as digits as its factorization.
10313553431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 29.
The spelling of 10313553431 in words is "ten billion, three hundred thirteen million, five hundred fifty-three thousand, four hundred thirty-one".
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