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10314113113 is a prime number
BaseRepresentation
bin10011001101100010…
…01110000001011001
3222121210211020022101
421212301032001121
5132110403104423
64423243123401
7513410341423
oct114661160131
928553736271
1010314113113
114413058927
121bba213561
13c84aba015
146dbb6b813
154057587ad
hex266c4e059

10314113113 has 2 divisors, whose sum is σ = 10314113114. Its totient is φ = 10314113112.

The previous prime is 10314113093. The next prime is 10314113153. The reversal of 10314113113 is 31131141301.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9001645129 + 1312467984 = 94877^2 + 36228^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10314113113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10314113153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157056556 + 5157056557.

It is an arithmetic number, because the mean of its divisors is an integer number (5157056557).

Almost surely, 210314113113 is an apocalyptic number.

It is an amenable number.

10314113113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10314113113 is an equidigital number, since it uses as much as digits as its factorization.

10314113113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 10314113113 its reverse (31131141301), we get a palindrome (41445254414).

The spelling of 10314113113 in words is "ten billion, three hundred fourteen million, one hundred thirteen thousand, one hundred thirteen".