103141244131 has 2 divisors, whose sum is σ = 103141244132. Its totient is φ = 103141244130.

The previous prime is 103141244099. The next prime is 103141244237. The reversal of 103141244131 is 131442141301.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 103141244131 - 2⁵ = 103141244099 is a prime.

It is a super-2 number, since 2×103141244131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103141244096 and 103141244105.

It is not a weakly prime, because it can be changed into another prime (103141244831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51570622065 + 51570622066.

It is an arithmetic number, because the mean of its divisors is an integer number (51570622066).

Almost surely, 2^103141244131 is an apocalyptic number.

103141244131 is a deficient number, since it is larger than the sum of its proper divisors (1).

103141244131 is an equidigital number, since it uses as much as digits as its factorization.

103141244131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 103141244131 its reverse (131442141301), we get a palindrome (234583385432).

The spelling of 103141244131 in words is "one hundred three billion, one hundred forty-one million, two hundred forty-four thousand, one hundred thirty-one".