1031420114 has 4 divisors (see below), whose sum is σ = 1547130174. Its totient is φ = 515710056.

The previous prime is 1031420113. The next prime is 1031420161. The reversal of 1031420114 is 4110241301.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4110241301 = 43 ⋅95587007.

It can be written as a sum of positive squares in only one way, i.e., 1005968089 + 25452025 = 31717^2 + 5045^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1031420092 and 1031420101.

It is not an unprimeable number, because it can be changed into a prime (1031420113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257855027 + ... + 257855030.

Almost surely, 2^1031420114 is an apocalyptic number.

1031420114 is a deficient number, since it is larger than the sum of its proper divisors (515710060).

1031420114 is an equidigital number, since it uses as much as digits as its factorization.

1031420114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 515710059.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1031420114 is about 32115.7300088290. The cubic root of 1031420114 is about 1010.3655553541.

Adding to 1031420114 its reverse (4110241301), we get a palindrome (5141661415).

The spelling of 1031420114 in words is "one billion, thirty-one million, four hundred twenty thousand, one hundred fourteen".