Base | Representation |
---|---|
bin | 10011001101100100… |
… | …00101011111001101 |
3 | 222121211020202221202 |
4 | 21212302011133031 |
5 | 132110432342201 |
6 | 4423252035245 |
7 | 513412305656 |
oct | 114662053715 |
9 | 28554222852 |
10 | 10314340301 |
11 | 44131a3591 |
12 | 1bba302b25 |
13 | c84b69555 |
14 | 6dbbca52d |
15 | 4057a0c6b |
hex | 266c857cd |
10314340301 has 2 divisors, whose sum is σ = 10314340302. Its totient is φ = 10314340300.
The previous prime is 10314340277. The next prime is 10314340313. The reversal of 10314340301 is 10304341301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10261487401 + 52852900 = 101299^2 + 7270^2 .
It is an emirp because it is prime and its reverse (10304341301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10314340301 - 214 = 10314323917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10314340391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157170150 + 5157170151.
It is an arithmetic number, because the mean of its divisors is an integer number (5157170151).
Almost surely, 210314340301 is an apocalyptic number.
It is an amenable number.
10314340301 is a deficient number, since it is larger than the sum of its proper divisors (1).
10314340301 is an equidigital number, since it uses as much as digits as its factorization.
10314340301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 10314340301 its reverse (10304341301), we get a palindrome (20618681602).
The spelling of 10314340301 in words is "ten billion, three hundred fourteen million, three hundred forty thousand, three hundred one".
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