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103150511407 is a prime number
BaseRepresentation
bin110000000010000111…
…1111110010100101111
3100212020201212220102101
41200010033332110233
53142223012331112
6115215305235531
710311110610646
oct1400417762457
9325221786371
10103150511407
113a822857a39
1217ba8a92ba7
13995b441888
144dc764635d
152a3ab0e757
hex18043fe52f

103150511407 has 2 divisors, whose sum is σ = 103150511408. Its totient is φ = 103150511406.

The previous prime is 103150511393. The next prime is 103150511441. The reversal of 103150511407 is 704115051301.

It is a weak prime.

It is an emirp because it is prime and its reverse (704115051301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103150511407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103150511447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51575255703 + 51575255704.

It is an arithmetic number, because the mean of its divisors is an integer number (51575255704).

Almost surely, 2103150511407 is an apocalyptic number.

103150511407 is a deficient number, since it is larger than the sum of its proper divisors (1).

103150511407 is an equidigital number, since it uses as much as digits as its factorization.

103150511407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2100, while the sum is 28.

Adding to 103150511407 its reverse (704115051301), we get a palindrome (807265562708).

The spelling of 103150511407 in words is "one hundred three billion, one hundred fifty million, five hundred eleven thousand, four hundred seven".