Base | Representation |
---|---|
bin | 110000000010000111… |
… | …1111110010100101111 |
3 | 100212020201212220102101 |
4 | 1200010033332110233 |
5 | 3142223012331112 |
6 | 115215305235531 |
7 | 10311110610646 |
oct | 1400417762457 |
9 | 325221786371 |
10 | 103150511407 |
11 | 3a822857a39 |
12 | 17ba8a92ba7 |
13 | 995b441888 |
14 | 4dc764635d |
15 | 2a3ab0e757 |
hex | 18043fe52f |
103150511407 has 2 divisors, whose sum is σ = 103150511408. Its totient is φ = 103150511406.
The previous prime is 103150511393. The next prime is 103150511441. The reversal of 103150511407 is 704115051301.
It is a weak prime.
It is an emirp because it is prime and its reverse (704115051301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103150511407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103150511447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51575255703 + 51575255704.
It is an arithmetic number, because the mean of its divisors is an integer number (51575255704).
Almost surely, 2103150511407 is an apocalyptic number.
103150511407 is a deficient number, since it is larger than the sum of its proper divisors (1).
103150511407 is an equidigital number, since it uses as much as digits as its factorization.
103150511407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2100, while the sum is 28.
Adding to 103150511407 its reverse (704115051301), we get a palindrome (807265562708).
The spelling of 103150511407 in words is "one hundred three billion, one hundred fifty million, five hundred eleven thousand, four hundred seven".
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