Base | Representation |
---|---|
bin | 1001011000101001011111… |
… | …1110101000101011010101 |
3 | 1100112111022010012210110021 |
4 | 2112022113332220223111 |
5 | 2323031414133133044 |
6 | 33540302234225141 |
7 | 2113345646116006 |
oct | 226122776505325 |
9 | 40474263183407 |
10 | 10319061224149 |
11 | 3319320053127 |
12 | 11a7aa08851b1 |
13 | 59b11100ca92 |
14 | 2796339c51ad |
15 | 12d650c31e84 |
hex | 96297fa8ad5 |
10319061224149 has 2 divisors, whose sum is σ = 10319061224150. Its totient is φ = 10319061224148.
The previous prime is 10319061224051. The next prime is 10319061224167. The reversal of 10319061224149 is 94142216091301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7114585313124 + 3204475911025 = 2667318^2 + 1790105^2 .
It is a cyclic number.
It is not a de Polignac number, because 10319061224149 - 233 = 10310471289557 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10319061222149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5159530612074 + 5159530612075.
It is an arithmetic number, because the mean of its divisors is an integer number (5159530612075).
Almost surely, 210319061224149 is an apocalyptic number.
It is an amenable number.
10319061224149 is a deficient number, since it is larger than the sum of its proper divisors (1).
10319061224149 is an equidigital number, since it uses as much as digits as its factorization.
10319061224149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 43.
The spelling of 10319061224149 in words is "ten trillion, three hundred nineteen billion, sixty-one million, two hundred twenty-four thousand, one hundred forty-nine".
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