Base | Representation |
---|---|
bin | 11110000010010000010… |
… | …11100001001010101111 |
3 | 10122122210001221212200022 |
4 | 33001020023201022233 |
5 | 113402020300130111 |
6 | 2110032400352355 |
7 | 134362666604066 |
oct | 17011013411257 |
9 | 3578701855608 |
10 | 1032003130031 |
11 | 368740954195 |
12 | 1480139156bb |
13 | 76418662883 |
14 | 37d409231dd |
15 | 1bca11702db |
hex | f0482e12af |
1032003130031 has 2 divisors, whose sum is σ = 1032003130032. Its totient is φ = 1032003130030.
The previous prime is 1032003129991. The next prime is 1032003130057. The reversal of 1032003130031 is 1300313002301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1032003130031 - 210 = 1032003129007 is a prime.
It is a super-2 number, since 2×10320031300312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1032003129991 and 1032003130009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1032003130831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516001565015 + 516001565016.
It is an arithmetic number, because the mean of its divisors is an integer number (516001565016).
Almost surely, 21032003130031 is an apocalyptic number.
1032003130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1032003130031 is an equidigital number, since it uses as much as digits as its factorization.
1032003130031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 1032003130031 its reverse (1300313002301), we get a palindrome (2332316132332).
The spelling of 1032003130031 in words is "one trillion, thirty-two billion, three million, one hundred thirty thousand, thirty-one".
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