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1032011053 is a prime number
BaseRepresentation
bin111101100000110…
…011110100101101
32122220220121000121
4331200303310231
54103143323203
6250223324541
734400643403
oct7540636455
92586817017
101032011053
1148a5a81a7
12249750751
13135a67638
149b0c1473
15609060bd
hex3d833d2d

1032011053 has 2 divisors, whose sum is σ = 1032011054. Its totient is φ = 1032011052.

The previous prime is 1032011047. The next prime is 1032011063. The reversal of 1032011053 is 3501102301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1022848324 + 9162729 = 31982^2 + 3027^2 .

It is an emirp because it is prime and its reverse (3501102301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1032011053 - 25 = 1032011021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1032011063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516005526 + 516005527.

It is an arithmetic number, because the mean of its divisors is an integer number (516005527).

Almost surely, 21032011053 is an apocalyptic number.

It is an amenable number.

1032011053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1032011053 is an equidigital number, since it uses as much as digits as its factorization.

1032011053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 1032011053 is about 32124.9288403881. The cubic root of 1032011053 is about 1010.5584772011.

Adding to 1032011053 its reverse (3501102301), we get a palindrome (4533113354).

It can be divided in two parts, 103201 and 1053, that multiplied together give a triangular number (108670653 = T14742).

The spelling of 1032011053 in words is "one billion, thirty-two million, eleven thousand, fifty-three".