Base | Representation |
---|---|
bin | 10111011101110001101000… |
… | …000111111111000100101111 |
3 | 111112101221101112121102010201 |
4 | 113131301220013333010233 |
5 | 102011322100101041421 |
6 | 1003253553025014331 |
7 | 30511020315502063 |
oct | 2735615007770457 |
9 | 445357345542121 |
10 | 103201221112111 |
11 | 2a97943495a711 |
12 | b6a91081843a7 |
13 | 4577aaac6bb55 |
14 | 1b6ad74053aa3 |
15 | bde779793b91 |
hex | 5ddc681ff12f |
103201221112111 has 2 divisors, whose sum is σ = 103201221112112. Its totient is φ = 103201221112110.
The previous prime is 103201221112049. The next prime is 103201221112141. The reversal of 103201221112111 is 111211122102301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103201221112111 - 227 = 103201086894383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103201221112141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51600610556055 + 51600610556056.
It is an arithmetic number, because the mean of its divisors is an integer number (51600610556056).
Almost surely, 2103201221112111 is an apocalyptic number.
103201221112111 is a deficient number, since it is larger than the sum of its proper divisors (1).
103201221112111 is an equidigital number, since it uses as much as digits as its factorization.
103201221112111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 103201221112111 its reverse (111211122102301), we get a palindrome (214412343214412).
The spelling of 103201221112111 in words is "one hundred three trillion, two hundred one billion, two hundred twenty-one million, one hundred twelve thousand, one hundred eleven".
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