Base | Representation |
---|---|
bin | 11110000010010010011… |
… | …01000101111011100101 |
3 | 10122122211021022012211211 |
4 | 33001021031011323211 |
5 | 113402034200214343 |
6 | 2110034213031421 |
7 | 134363265660406 |
oct | 17011115057345 |
9 | 3578737265754 |
10 | 1032020319973 |
11 | 36874a625255 |
12 | 148019625571 |
13 | 7641c0a0c36 |
14 | 37d42d199ad |
15 | 1bca291879d |
hex | f049345ee5 |
1032020319973 has 2 divisors, whose sum is σ = 1032020319974. Its totient is φ = 1032020319972.
The previous prime is 1032020319949. The next prime is 1032020319983. The reversal of 1032020319973 is 3799130202301.
1032020319973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1002397435204 + 29622884769 = 1001198^2 + 172113^2 .
It is a cyclic number.
It is not a de Polignac number, because 1032020319973 - 221 = 1032018222821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1032020319943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516010159986 + 516010159987.
It is an arithmetic number, because the mean of its divisors is an integer number (516010159987).
Almost surely, 21032020319973 is an apocalyptic number.
It is an amenable number.
1032020319973 is a deficient number, since it is larger than the sum of its proper divisors (1).
1032020319973 is an equidigital number, since it uses as much as digits as its factorization.
1032020319973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 40.
The spelling of 1032020319973 in words is "one trillion, thirty-two billion, twenty million, three hundred nineteen thousand, nine hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •