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10323040354142 = 25161520177071
BaseRepresentation
bin1001011000111000010100…
…1001110011111101011110
31100112212120102122112122012
42112032011021303331132
52323113041312313032
633542201140551222
72113546364141045
oct226160511637536
940485512575565
1010323040354142
11331aa8218240a
1211a88113b2512
1359b5c6505079
142798d026555c
1512d7d52336b2
hex96385273f5e

10323040354142 has 4 divisors (see below), whose sum is σ = 15484560531216. Its totient is φ = 5161520177070.

The previous prime is 10323040354129. The next prime is 10323040354171. The reversal of 10323040354142 is 24145304032301.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 10323040354099 and 10323040354108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2580760088534 + ... + 2580760088537.

It is an arithmetic number, because the mean of its divisors is an integer number (3871140132804).

Almost surely, 210323040354142 is an apocalyptic number.

10323040354142 is a deficient number, since it is larger than the sum of its proper divisors (5161520177074).

10323040354142 is an equidigital number, since it uses as much as digits as its factorization.

10323040354142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5161520177073.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 10323040354142 its reverse (24145304032301), we get a palindrome (34468344386443).

The spelling of 10323040354142 in words is "ten trillion, three hundred twenty-three billion, forty million, three hundred fifty-four thousand, one hundred forty-two".

Divisors: 1 2 5161520177071 10323040354142