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1032313111241 is a prime number
BaseRepresentation
bin11110000010110101010…
…10000000001011001001
310122200120200020112221212
433001122222000023021
5113403134124024431
62110123232342505
7134403452444306
oct17013252001311
93580520215855
101032313111241
1136888a925705
1214809b6a4a35
13764679467c9
1437d6db740ad
151bcbd4a172b
hexf05aa802c9

1032313111241 has 2 divisors, whose sum is σ = 1032313111242. Its totient is φ = 1032313111240.

The previous prime is 1032313111201. The next prime is 1032313111243. The reversal of 1032313111241 is 1421113132301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 856503975625 + 175809135616 = 925475^2 + 419296^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1032313111241 is a prime.

Together with 1032313111243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1032313111243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516156555620 + 516156555621.

It is an arithmetic number, because the mean of its divisors is an integer number (516156555621).

Almost surely, 21032313111241 is an apocalyptic number.

It is an amenable number.

1032313111241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1032313111241 is an equidigital number, since it uses as much as digits as its factorization.

1032313111241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1032313111241 its reverse (1421113132301), we get a palindrome (2453426243542).

The spelling of 1032313111241 in words is "one trillion, thirty-two billion, three hundred thirteen million, one hundred eleven thousand, two hundred forty-one".