Base | Representation |
---|---|
bin | 110000000100100011… |
… | …0111100010111000011 |
3 | 100212110102021111002222 |
4 | 1200021012330113003 |
5 | 3142404344431042 |
6 | 115231340401255 |
7 | 10313120530631 |
oct | 1401106742703 |
9 | 325412244088 |
10 | 103232030147 |
11 | 3a8648761a4 |
12 | 1801024622b |
13 | 99722b430c |
14 | 4dd43c6351 |
15 | 2a42d632d2 |
hex | 18091bc5c3 |
103232030147 has 2 divisors, whose sum is σ = 103232030148. Its totient is φ = 103232030146.
The previous prime is 103232030089. The next prime is 103232030173. The reversal of 103232030147 is 741030232301.
It is an a-pointer prime, because the next prime (103232030173) can be obtained adding 103232030147 to its sum of digits (26).
It is a strong prime.
It is an emirp because it is prime and its reverse (741030232301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103232030147 - 220 = 103230981571 is a prime.
It is a super-2 number, since 2×1032320301472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103232030347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51616015073 + 51616015074.
It is an arithmetic number, because the mean of its divisors is an integer number (51616015074).
Almost surely, 2103232030147 is an apocalyptic number.
103232030147 is a deficient number, since it is larger than the sum of its proper divisors (1).
103232030147 is an equidigital number, since it uses as much as digits as its factorization.
103232030147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 26.
Adding to 103232030147 its reverse (741030232301), we get a palindrome (844262262448).
The spelling of 103232030147 in words is "one hundred three billion, two hundred thirty-two million, thirty thousand, one hundred forty-seven".
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