Base | Representation |
---|---|
bin | 1001011000111000111101… |
… | …1010100010010110000001 |
3 | 1100112220000102120222220001 |
4 | 2112032033122202112001 |
5 | 2323113414400314333 |
6 | 33542230210520001 |
7 | 2113553554350643 |
oct | 226161732422601 |
9 | 40486012528801 |
10 | 10323212510593 |
11 | 3320060378074 |
12 | 11a885ab96001 |
13 | 59b623090aa8 |
14 | 27990907a893 |
15 | 12d7e53dcb7d |
hex | 9638f6a2581 |
10323212510593 has 2 divisors, whose sum is σ = 10323212510594. Its totient is φ = 10323212510592.
The previous prime is 10323212510591. The next prime is 10323212510701. The reversal of 10323212510593 is 39501521232301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5642943238144 + 4680269272449 = 2375488^2 + 2163393^2 .
It is a cyclic number.
It is not a de Polignac number, because 10323212510593 - 21 = 10323212510591 is a prime.
Together with 10323212510591, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10323212510591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5161606255296 + 5161606255297.
It is an arithmetic number, because the mean of its divisors is an integer number (5161606255297).
Almost surely, 210323212510593 is an apocalyptic number.
It is an amenable number.
10323212510593 is a deficient number, since it is larger than the sum of its proper divisors (1).
10323212510593 is an equidigital number, since it uses as much as digits as its factorization.
10323212510593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 37.
Adding to 10323212510593 its reverse (39501521232301), we get a palindrome (49824733742894).
The spelling of 10323212510593 in words is "ten trillion, three hundred twenty-three billion, two hundred twelve million, five hundred ten thousand, five hundred ninety-three".
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