Base | Representation |
---|---|
bin | 10111011110001110101100… |
… | …100011101111100100000011 |
3 | 111112111220221211011221010121 |
4 | 113132032230203233210003 |
5 | 102012330011101312441 |
6 | 1003320154145441111 |
7 | 30513203643656341 |
oct | 2736165443574403 |
9 | 445456854157117 |
10 | 103232434010371 |
11 | 2a9906a180a0a6 |
12 | b6b3179340197 |
13 | 457aa136c3213 |
14 | 1b6c6955c8991 |
15 | be04a4b04dd1 |
hex | 5de3ac8ef903 |
103232434010371 has 2 divisors, whose sum is σ = 103232434010372. Its totient is φ = 103232434010370.
The previous prime is 103232434010347. The next prime is 103232434010441. The reversal of 103232434010371 is 173010434232301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103232434010371 - 25 = 103232434010339 is a prime.
It is a super-2 number, since 2×1032324340103712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103232434010311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51616217005185 + 51616217005186.
It is an arithmetic number, because the mean of its divisors is an integer number (51616217005186).
Almost surely, 2103232434010371 is an apocalyptic number.
103232434010371 is a deficient number, since it is larger than the sum of its proper divisors (1).
103232434010371 is an equidigital number, since it uses as much as digits as its factorization.
103232434010371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 34.
Adding to 103232434010371 its reverse (173010434232301), we get a palindrome (276242868242672).
The spelling of 103232434010371 in words is "one hundred three trillion, two hundred thirty-two billion, four hundred thirty-four million, ten thousand, three hundred seventy-one".
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