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103233124439 is a prime number
BaseRepresentation
bin110000000100100101…
…1000111100001010111
3100212110111100002012022
41200021023013201113
53142410134440224
6115231420043355
710313133036164
oct1401113074127
9325414302168
10103233124439
113a865453375
121801069355b
1399725a8423
144dd45cd06b
152a42ecc65e
hex18092c7857

103233124439 has 2 divisors, whose sum is σ = 103233124440. Its totient is φ = 103233124438.

The previous prime is 103233124429. The next prime is 103233124493. The reversal of 103233124439 is 934421332301.

Together with next prime (103233124493) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (934421332301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103233124439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103233124399 and 103233124408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103233124429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51616562219 + 51616562220.

It is an arithmetic number, because the mean of its divisors is an integer number (51616562220).

Almost surely, 2103233124439 is an apocalyptic number.

103233124439 is a deficient number, since it is larger than the sum of its proper divisors (1).

103233124439 is an equidigital number, since it uses as much as digits as its factorization.

103233124439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 35.

The spelling of 103233124439 in words is "one hundred three billion, two hundred thirty-three million, one hundred twenty-four thousand, four hundred thirty-nine".