Base | Representation |
---|---|
bin | 110000000101001000… |
… | …0001111001001101111 |
3 | 100212111202102122001111 |
4 | 1200022100033021233 |
5 | 3142424304244011 |
6 | 115233304252451 |
7 | 10313443042624 |
oct | 1401220171157 |
9 | 325452378044 |
10 | 103251243631 |
11 | 3a8746a9608 |
12 | 18016771127 |
13 | 9976280743 |
14 | 4dd6b8834b |
15 | 2a448ab121 |
hex | 180a40f26f |
103251243631 has 2 divisors, whose sum is σ = 103251243632. Its totient is φ = 103251243630.
The previous prime is 103251243611. The next prime is 103251243643. The reversal of 103251243631 is 136342152301.
It is a strong prime.
It is an emirp because it is prime and its reverse (136342152301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103251243631 - 219 = 103250719343 is a prime.
It is a super-2 number, since 2×1032512436312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103251243593 and 103251243602.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103251243611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51625621815 + 51625621816.
It is an arithmetic number, because the mean of its divisors is an integer number (51625621816).
Almost surely, 2103251243631 is an apocalyptic number.
103251243631 is a deficient number, since it is larger than the sum of its proper divisors (1).
103251243631 is an equidigital number, since it uses as much as digits as its factorization.
103251243631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 103251243631 its reverse (136342152301), we get a palindrome (239593395932).
The spelling of 103251243631 in words is "one hundred three billion, two hundred fifty-one million, two hundred forty-three thousand, six hundred thirty-one".
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