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103300312311302 = 251650156155651
BaseRepresentation
bin10111011111001101111010…
…011010111010011000000110
3111112202102011101011220001012
4113133031322122322120012
5102014433014422430202
61003411301445202222
730521126016005411
oct2737157232723006
9445672141156035
10103300312311302
112aa074642a2267
12b704361700372
1345842403c3122
141b71a94506b78
15be2128d14152
hex5df37a6ba606

103300312311302 has 4 divisors (see below), whose sum is σ = 154950468466956. Its totient is φ = 51650156155650.

The previous prime is 103300312311299. The next prime is 103300312311337. The reversal of 103300312311302 is 203113213003301.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1033003123113022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25825078077824 + ... + 25825078077827.

It is an arithmetic number, because the mean of its divisors is an integer number (38737617116739).

Almost surely, 2103300312311302 is an apocalyptic number.

103300312311302 is a deficient number, since it is larger than the sum of its proper divisors (51650156155654).

103300312311302 is an equidigital number, since it uses as much as digits as its factorization.

103300312311302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51650156155653.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 103300312311302 its reverse (203113213003301), we get a palindrome (306413525314603).

The spelling of 103300312311302 in words is "one hundred three trillion, three hundred billion, three hundred twelve million, three hundred eleven thousand, three hundred two".

Divisors: 1 2 51650156155651 103300312311302