1033011103013 has 2 divisors, whose sum is σ = 1033011103014. Its totient is φ = 1033011103012.

The previous prime is 1033011102967. The next prime is 1033011103021. The reversal of 1033011103013 is 3103011103301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 860621723809 + 172389379204 = 927697^2 + 415198^2 .

It is an emirp because it is prime and its reverse (3103011103301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1033011103013 - 2¹⁶ = 1033011037477 is a prime.

It is a super-2 number, since 2×1033011103013² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1033011102982 and 1033011103000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1033011103063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516505551506 + 516505551507.

It is an arithmetic number, because the mean of its divisors is an integer number (516505551507).

Almost surely, 2^{1033011103013} is an apocalyptic number.

It is an amenable number.

1033011103013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1033011103013 is an equidigital number, since it uses as much as digits as its factorization.

1033011103013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1033011103013 its reverse (3103011103301), we get a palindrome (4136022206314).

The spelling of 1033011103013 in words is "one trillion, thirty-three billion, eleven million, one hundred three thousand, thirteen".