Base | Representation |
---|---|
bin | 11110000100010011010… |
… | …00010111110101011011 |
3 | 10122202121121012021100121 |
4 | 33002021220113311123 |
5 | 113411242402304034 |
6 | 2110333344214111 |
7 | 134432132264161 |
oct | 17021150276533 |
9 | 3582547167317 |
10 | 1033101213019 |
11 | 36915477a197 |
12 | 14827b60a337 |
13 | 76561cc1b15 |
14 | 380066c3231 |
15 | 1bd177781b4 |
hex | f089a17d5b |
1033101213019 has 2 divisors, whose sum is σ = 1033101213020. Its totient is φ = 1033101213018.
The previous prime is 1033101212987. The next prime is 1033101213029. The reversal of 1033101213019 is 9103121013301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1033101213019 - 25 = 1033101212987 is a prime.
It is a super-2 number, since 2×10331012130192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1033101212984 and 1033101213002.
It is not a weakly prime, because it can be changed into another prime (1033101213029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516550606509 + 516550606510.
It is an arithmetic number, because the mean of its divisors is an integer number (516550606510).
Almost surely, 21033101213019 is an apocalyptic number.
1033101213019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1033101213019 is an equidigital number, since it uses as much as digits as its factorization.
1033101213019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 1033101213019 in words is "one trillion, thirty-three billion, one hundred one million, two hundred thirteen thousand, nineteen".
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