Base | Representation |
---|---|
bin | 10111011111010111111110… |
… | …101110101001011110111001 |
3 | 111112210110001201112120211121 |
4 | 113133113332232221132321 |
5 | 102020122134213341324 |
6 | 1003420250234425241 |
7 | 30521660624646145 |
oct | 2737277656513671 |
9 | 445713051476747 |
10 | 103311122012089 |
11 | 2aa11001073482 |
12 | b706479892221 |
13 | 4585273a7ba94 |
14 | 1b723dbddc225 |
15 | be255cd135e4 |
hex | 5df5feba97b9 |
103311122012089 has 2 divisors, whose sum is σ = 103311122012090. Its totient is φ = 103311122012088.
The previous prime is 103311122012071. The next prime is 103311122012129. The reversal of 103311122012089 is 980210221113301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79696381762089 + 23614740250000 = 8927283^2 + 4859500^2 .
It is a cyclic number.
It is not a de Polignac number, because 103311122012089 - 233 = 103302532077497 is a prime.
It is not a weakly prime, because it can be changed into another prime (103311122022089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51655561006044 + 51655561006045.
It is an arithmetic number, because the mean of its divisors is an integer number (51655561006045).
Almost surely, 2103311122012089 is an apocalyptic number.
It is an amenable number.
103311122012089 is a deficient number, since it is larger than the sum of its proper divisors (1).
103311122012089 is an equidigital number, since it uses as much as digits as its factorization.
103311122012089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 34.
The spelling of 103311122012089 in words is "one hundred three trillion, three hundred eleven billion, one hundred twenty-two million, twelve thousand, eighty-nine".
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