Base | Representation |
---|---|
bin | 10111011111011001101111… |
… | …011000111000000011100100 |
3 | 111112210121221110010112012102 |
4 | 113133121233120320003210 |
5 | 102020140022101130040 |
6 | 1003421201554311232 |
7 | 30522055515460100 |
oct | 2737315730700344 |
9 | 445717843115172 |
10 | 103313012130020 |
11 | 2aa11890a8a010 |
12 | b706906888518 |
13 | 45854b5532664 |
14 | 1b7253b052900 |
15 | be261dc1d515 |
hex | 5df66f6380e4 |
103313012130020 has 144 divisors (see below), whose sum is σ = 275360286257280. Its totient is φ = 32197035225600.
The previous prime is 103313012130017. The next prime is 103313012130037. The reversal of 103313012130020 is 20031210313301.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 103313012129974 and 103313012130001.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 78265841 + ... + 79574919.
It is an arithmetic number, because the mean of its divisors is an integer number (1912224210120).
Almost surely, 2103313012130020 is an apocalyptic number.
103313012130020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 103313012130020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (137680143128640).
103313012130020 is an abundant number, since it is smaller than the sum of its proper divisors (172047274127260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103313012130020 is a wasteful number, since it uses less digits than its factorization.
103313012130020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1316434 (or 1316425 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 103313012130020 its reverse (20031210313301), we get a palindrome (123344222443321).
The spelling of 103313012130020 in words is "one hundred three trillion, three hundred thirteen billion, twelve million, one hundred thirty thousand, twenty".
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