Base | Representation |
---|---|
bin | 10011001111100110… |
… | …01010011110111111 |
3 | 222200000100111122011 |
4 | 21213303022132333 |
5 | 132124314301002 |
6 | 4425101432051 |
7 | 514010311036 |
oct | 114763123677 |
9 | 28600314564 |
10 | 10331400127 |
11 | 4421895914 |
12 | 2003b6b627 |
13 | c88560619 |
14 | 70018b71d |
15 | 4070208d7 |
hex | 267cca7bf |
10331400127 has 2 divisors, whose sum is σ = 10331400128. Its totient is φ = 10331400126.
The previous prime is 10331400113. The next prime is 10331400137. The reversal of 10331400127 is 72100413301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10331400127 - 223 = 10323011519 is a prime.
It is a super-2 number, since 2×103314001272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10331400098 and 10331400107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10331400137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5165700063 + 5165700064.
It is an arithmetic number, because the mean of its divisors is an integer number (5165700064).
Almost surely, 210331400127 is an apocalyptic number.
10331400127 is a deficient number, since it is larger than the sum of its proper divisors (1).
10331400127 is an equidigital number, since it uses as much as digits as its factorization.
10331400127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 10331400127 its reverse (72100413301), we get a palindrome (82431813428).
The spelling of 10331400127 in words is "ten billion, three hundred thirty-one million, four hundred thousand, one hundred twenty-seven".
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