Base | Representation |
---|---|
bin | 10111011111100000010101… |
… | …111011001001101001001011 |
3 | 111112211022020111021112000002 |
4 | 113133200111323021221023 |
5 | 102020244031340200412 |
6 | 1003424333231433215 |
7 | 30522426264642263 |
oct | 2737402573115113 |
9 | 445738214245002 |
10 | 103320101100107 |
11 | 2aa14899581181 |
12 | b70816498580b |
13 | 45860750b9808 |
14 | 1b72a1072c7a3 |
15 | be28d625ddc2 |
hex | 5df815ec9a4b |
103320101100107 has 2 divisors, whose sum is σ = 103320101100108. Its totient is φ = 103320101100106.
The previous prime is 103320101100091. The next prime is 103320101100109. The reversal of 103320101100107 is 701001101023301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103320101100107 - 24 = 103320101100091 is a prime.
It is a super-2 number, since 2×1033201011001072 (a number of 29 digits) contains 22 as substring.
Together with 103320101100109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (103320101100109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51660050550053 + 51660050550054.
It is an arithmetic number, because the mean of its divisors is an integer number (51660050550054).
Almost surely, 2103320101100107 is an apocalyptic number.
103320101100107 is a deficient number, since it is larger than the sum of its proper divisors (1).
103320101100107 is an equidigital number, since it uses as much as digits as its factorization.
103320101100107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 103320101100107 its reverse (701001101023301), we get a palindrome (804321202123408).
The spelling of 103320101100107 in words is "one hundred three trillion, three hundred twenty billion, one hundred one million, one hundred thousand, one hundred seven".
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