Base | Representation |
---|---|
bin | 10111011111100011001001… |
… | …111111000011011011110100 |
3 | 111112211121001000200020222000 |
4 | 113133203021333003123310 |
5 | 102020321223214202012 |
6 | 1003425553104335300 |
7 | 30522564166234155 |
oct | 2737431177033364 |
9 | 445747030606860 |
10 | 103323122022132 |
11 | 2aa160a9831651 |
12 | b708868614530 |
13 | 4586436c1803c |
14 | 1b72c19a1d92c |
15 | be2a11586ddc |
hex | 5df8c9fc36f4 |
103323122022132 has 24 divisors (see below), whose sum is σ = 267874760798400. Its totient is φ = 34441040674008.
The previous prime is 103323122022103. The next prime is 103323122022137. The reversal of 103323122022132 is 231220221323301.
103323122022132 is a `hidden beast` number, since 1 + 0 + 3 + 323 + 1 + 2 + 202 + 2 + 132 = 666.
It is a super-4 number, since 4×1033231220221324 (a number of 57 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 103323122022096 and 103323122022105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103323122022137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 478347787032 + ... + 478347787247.
It is an arithmetic number, because the mean of its divisors is an integer number (11161448366600).
Almost surely, 2103323122022132 is an apocalyptic number.
103323122022132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
103323122022132 is an abundant number, since it is smaller than the sum of its proper divisors (164551638776268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103323122022132 is a wasteful number, since it uses less digits than its factorization.
103323122022132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 956695574292 (or 956695574284 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 103323122022132 its reverse (231220221323301), we get a palindrome (334543343345433).
The spelling of 103323122022132 in words is "one hundred three trillion, three hundred twenty-three billion, one hundred twenty-two million, twenty-two thousand, one hundred thirty-two".
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