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103331199953 is a prime number
BaseRepresentation
bin110000000111100000…
…1001111101111010001
3100212201022212211111202
41200033001033233101
53143110241344303
6115245242120545
710315433464502
oct1401701175721
9325638784452
10103331199953
113a90584aa13
12180394b0155
1399899c6c87
14500363cba9
152a4b901c88
hex180f04fbd1

103331199953 has 2 divisors, whose sum is σ = 103331199954. Its totient is φ = 103331199952.

The previous prime is 103331199889. The next prime is 103331200019. The reversal of 103331199953 is 359991133301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94825195969 + 8506003984 = 307937^2 + 92228^2 .

It is a cyclic number.

It is not a de Polignac number, because 103331199953 - 26 = 103331199889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103331199898 and 103331199907.

It is not a weakly prime, because it can be changed into another prime (103331199253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51665599976 + 51665599977.

It is an arithmetic number, because the mean of its divisors is an integer number (51665599977).

Almost surely, 2103331199953 is an apocalyptic number.

It is an amenable number.

103331199953 is a deficient number, since it is larger than the sum of its proper divisors (1).

103331199953 is an equidigital number, since it uses as much as digits as its factorization.

103331199953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 295245, while the sum is 47.

The spelling of 103331199953 in words is "one hundred three billion, three hundred thirty-one million, one hundred ninety-nine thousand, nine hundred fifty-three".