Search a number
-
+
103332131221057 is a prime number
BaseRepresentation
bin10111011111101011100010…
…111110011010111001000001
3111112212110021220001222112021
4113133223202332122321001
5102020443201043033212
61003434043055001441
730523333353200224
oct2737534276327101
9445773256058467
10103332131221057
112aa19a022360a2
12b70a561809281
13458724156938b
141b7343234b5bb
15be2d8c47e307
hex5dfae2f9ae41

103332131221057 has 2 divisors, whose sum is σ = 103332131221058. Its totient is φ = 103332131221056.

The previous prime is 103332131220947. The next prime is 103332131221087. The reversal of 103332131221057 is 750122131233301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78405517286721 + 24926613934336 = 8854689^2 + 4992656^2 .

It is an emirp because it is prime and its reverse (750122131233301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103332131221057 - 239 = 102782375407169 is a prime.

It is not a weakly prime, because it can be changed into another prime (103332131221087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51666065610528 + 51666065610529.

It is an arithmetic number, because the mean of its divisors is an integer number (51666065610529).

Almost surely, 2103332131221057 is an apocalyptic number.

It is an amenable number.

103332131221057 is a deficient number, since it is larger than the sum of its proper divisors (1).

103332131221057 is an equidigital number, since it uses as much as digits as its factorization.

103332131221057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22680, while the sum is 34.

Adding to 103332131221057 its reverse (750122131233301), we get a palindrome (853454262454358).

The spelling of 103332131221057 in words is "one hundred three trillion, three hundred thirty-two billion, one hundred thirty-one million, two hundred twenty-one thousand, fifty-seven".