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103414314011 is a prime number
BaseRepresentation
bin110000001001111111…
…0010011010000011011
3100212221010021110120012
41200103332103100123
53143243031022021
6115301411352135
710320463110521
oct1402376232033
9325833243505
10103414314011
113a948758818
12180612b264b
1399a0ca78a8
1450106b6311
152a53d6d35b
hex1813f9341b

103414314011 has 2 divisors, whose sum is σ = 103414314012. Its totient is φ = 103414314010.

The previous prime is 103414313993. The next prime is 103414314013. The reversal of 103414314011 is 110413414301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103414314011 - 222 = 103410119707 is a prime.

Together with 103414314013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (103414314013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51707157005 + 51707157006.

It is an arithmetic number, because the mean of its divisors is an integer number (51707157006).

Almost surely, 2103414314011 is an apocalyptic number.

103414314011 is a deficient number, since it is larger than the sum of its proper divisors (1).

103414314011 is an equidigital number, since it uses as much as digits as its factorization.

103414314011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 103414314011 its reverse (110413414301), we get a palindrome (213827728312).

The spelling of 103414314011 in words is "one hundred three billion, four hundred fourteen million, three hundred fourteen thousand, eleven".