Base | Representation |
---|---|
bin | 1001011001111100110101… |
… | …1100101110011101111001 |
3 | 1100121122001020220221002110 |
4 | 2112133031130232131321 |
5 | 2323413223341003423 |
6 | 33554442214122533 |
7 | 2115100232223504 |
oct | 226371534563571 |
9 | 40548036827073 |
10 | 10341433141113 |
11 | 33278604534a8 |
12 | 11b02a5050449 |
13 | 5a0267c1ca79 |
14 | 27a756cda13b |
15 | 12e00ed28193 |
hex | 967cd72e779 |
10341433141113 has 64 divisors (see below), whose sum is σ = 14746944499200. Its totient is φ = 6435010283520.
The previous prime is 10341433141103. The next prime is 10341433141159. The reversal of 10341433141113 is 31114133414301.
It is not a de Polignac number, because 10341433141113 - 26 = 10341433141049 is a prime.
It is a super-2 number, since 2×103414331411132 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (10341433141103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 585675781 + ... + 585693437.
It is an arithmetic number, because the mean of its divisors is an integer number (230421007800).
Almost surely, 210341433141113 is an apocalyptic number.
It is an amenable number.
10341433141113 is a deficient number, since it is larger than the sum of its proper divisors (4405511358087).
10341433141113 is a wasteful number, since it uses less digits than its factorization.
10341433141113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19602.
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 10341433141113 its reverse (31114133414301), we get a palindrome (41455566555414).
The spelling of 10341433141113 in words is "ten trillion, three hundred forty-one billion, four hundred thirty-three million, one hundred forty-one thousand, one hundred thirteen".
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