10343312400613 has 2 divisors, whose sum is σ = 10343312400614. Its totient is φ = 10343312400612.

The previous prime is 10343312400581. The next prime is 10343312400649. The reversal of 10343312400613 is 31600421334301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7305008917284 + 3038303483329 = 2702778^2 + 1743073^2 .

It is an emirp because it is prime and its reverse (31600421334301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10343312400613 - 2⁵ = 10343312400581 is a prime.

It is a super-2 number, since 2×10343312400613² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10343312409613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5171656200306 + 5171656200307.

It is an arithmetic number, because the mean of its divisors is an integer number (5171656200307).

Almost surely, 2^{10343312400613} is an apocalyptic number.

It is an amenable number.

10343312400613 is a deficient number, since it is larger than the sum of its proper divisors (1).

10343312400613 is an equidigital number, since it uses as much as digits as its factorization.

10343312400613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 10343312400613 its reverse (31600421334301), we get a palindrome (41943733734914).

The spelling of 10343312400613 in words is "ten trillion, three hundred forty-three billion, three hundred twelve million, four hundred thousand, six hundred thirteen".