10343313103 has 4 divisors (see below), whose sum is σ = 10538470008. Its totient is φ = 10148156200.

The previous prime is 10343313083. The next prime is 10343313139. The reversal of 10343313103 is 30131334301.

10343313103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30131334301 = 487 ⋅61871323.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10343313103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10343313143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97578373 + ... + 97578478.

It is an arithmetic number, because the mean of its divisors is an integer number (2634617502).

Almost surely, 2^10343313103 is an apocalyptic number.

10343313103 is a deficient number, since it is larger than the sum of its proper divisors (195156905).

10343313103 is an equidigital number, since it uses as much as digits as its factorization.

10343313103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 195156904.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 10343313103 its reverse (30131334301), we get a palindrome (40474647404).

The spelling of 10343313103 in words is "ten billion, three hundred forty-three million, three hundred thirteen thousand, one hundred three".