Base | Representation |
---|---|
bin | 1001011010000011110110… |
… | …0000100111110000101101 |
3 | 1100121210220021121100022202 |
4 | 2112200331200213300231 |
5 | 2323431101140213123 |
6 | 33555352534351245 |
7 | 2115164641443221 |
oct | 226407540476055 |
9 | 40553807540282 |
10 | 10343313210413 |
11 | 3328635726387 |
12 | 11b072a7bb525 |
13 | 5a04a7595901 |
14 | 27a894896781 |
15 | 12e0bedeaa28 |
hex | 9683d827c2d |
10343313210413 has 2 divisors, whose sum is σ = 10343313210414. Its totient is φ = 10343313210412.
The previous prime is 10343313210367. The next prime is 10343313210457. The reversal of 10343313210413 is 31401231334301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10045876047529 + 297437162884 = 3169523^2 + 545378^2 .
It is a cyclic number.
It is not a de Polignac number, because 10343313210413 - 28 = 10343313210157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10343313213413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5171656605206 + 5171656605207.
It is an arithmetic number, because the mean of its divisors is an integer number (5171656605207).
Almost surely, 210343313210413 is an apocalyptic number.
It is an amenable number.
10343313210413 is a deficient number, since it is larger than the sum of its proper divisors (1).
10343313210413 is an equidigital number, since it uses as much as digits as its factorization.
10343313210413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 10343313210413 its reverse (31401231334301), we get a palindrome (41744544544714).
The spelling of 10343313210413 in words is "ten trillion, three hundred forty-three billion, three hundred thirteen million, two hundred ten thousand, four hundred thirteen".
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