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10343411233 is a prime number
BaseRepresentation
bin10011010001000001…
…11110111000100001
3222200211221201202221
421220200332320201
5132140403124413
64430211111041
7514214354611
oct115040767041
928624851687
1010343411233
114428649a51
122007ba2481
13c8aba769c
147019d6a41
154080e468d
hex26883ee21

10343411233 has 2 divisors, whose sum is σ = 10343411234. Its totient is φ = 10343411232.

The previous prime is 10343411149. The next prime is 10343411249. The reversal of 10343411233 is 33211434301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10337398929 + 6012304 = 101673^2 + 2452^2 .

It is an emirp because it is prime and its reverse (33211434301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10343411233 - 217 = 10343280161 is a prime.

It is a super-3 number, since 3×103434112333 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10343411198 and 10343411207.

It is not a weakly prime, because it can be changed into another prime (10343411033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5171705616 + 5171705617.

It is an arithmetic number, because the mean of its divisors is an integer number (5171705617).

Almost surely, 210343411233 is an apocalyptic number.

It is an amenable number.

10343411233 is a deficient number, since it is larger than the sum of its proper divisors (1).

10343411233 is an equidigital number, since it uses as much as digits as its factorization.

10343411233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10343411233 its reverse (33211434301), we get a palindrome (43554845534).

The spelling of 10343411233 in words is "ten billion, three hundred forty-three million, four hundred eleven thousand, two hundred thirty-three".